A quick memory question:

Does a signed byte, word or quad use more memory than an unsigned one? I understand that a byte is 8 bits, word 16, quad 32, but is a signed byte still 8 bits or is it 9? If it is 9, given that you cannot set bit accurate pointers, I would have to give up the next 7 bits (big deal) and set the next value at the next complete byte, correct?

Such as:

sbyte[Ptr] = 26;
sbyte[Ptr+2] = 13;

Or can I do

sbyte[Ptr] = 26;
sbyte[Ptr+1] = 13;

without overwriting a portion of the first value?

Thanks,
Devon

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--- Square's making money. We're making art.

-nt-

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--- Square's making money. We're making art.